Suppose a study of speeding violations and drivers who use cell phones produced the following fictional data: Table 3.2.


Speeding violation in the last yearNo speeding violation in the last yearTotal
Uses cell phone while driving25280305
Does not use cell phone while driving45405450
Total70685755

The total number of people in the sample is 755. The row totals are 305 and 450. The column totals are 70 and

685. Notice that 305 + 450 = 755 and 70 + 685 = 755.

Calculate the following probabilities using the table.

a. Find P(Driver is a cell phone user).

b. Find P(driver had no violation in the last year).

c. Find P(Driver had no violation in the last year AND was a cell phone user).

d. Find P(Driver is a cell phone user OR driver had no violation in the last year).

e. Find P(Driver is a cell phone user GIVEN driver had a violation in the last year).

f. Find P(Driver had no violation last year GIVEN driver was not a cell phone user)

Short Answer

Expert verified

Part a: P(Driver is a cell phone user) =305755

Part b: P(driver had no violation in the last year) =685755

Part c: P(Driver had no violation in the last year AND was a cell phone user) =280755

Part d: P(Driver is a cell phone user OR driver had no violation in the last year) =710755

Part e: P(Driver is a cell phone user GIVEN driver had a violation in the last year) =2570

Part f: P(Driver had no violation last year GIVEN driver was not a cell phone user) =405450

Step by step solution

01

Given information (Part a)

number of cell phone users = 305, Total number of users in study = 755.

02

Probability of drivers as cell phone users

Part a:numberofcellphoneuserstotalnumberinstudy=305755

03

Given information (Part b)

number that had no violation = 685, Total number of users in study = 755.

04

P(driver had no violation in the last year)  

Part b:numberthathadnoviolationtotalnumberinstudy=685755

05

Given information (Part c)

the number had no violation in the last year AND was a cell phone user = 280, total number of study = 755

06

P(Driver had no violation in the last year AND was a cell phone user) 

Part c:numberofdriverhadnoviolationinlastyearandcellphoneusertotalnumberofstudy=280755

07

Given information (Part d)

Probability of driver is a cell phone user OR driver had no violations in the last year = Probability of driver as cell phone user + Probability of driver had no violation last year - Probability of driver had no violation last year AND was a cell phone user

08

Probability of driver is a cell phone user OR driver had no violations in the last year 

Part d:305755+685755-280755=710755

09

Given information (Part e)

number of drivers had violations in the last year while using cell phones = 25. Total drivers had violations in the last year = 70.

10

Step 2: P (Driver is a cell phone user GIVEN driver had a violation in the last year)

part e:2570

11

Given information (Part f)

P(Driver had no violation last year GIVEN driver was not a cell phone user), number of the driver had no violation last year but not a cell phone user = 405 Total number of the driver was not a cell phone user = 450

12

P(Driver had no violation last year GIVEN driver was not a cell phone user) 

part f:405450

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following information to answer the next 12exercises. The graph shown is based on more than 1,70,000interviews done by Gallup that took place from January through December 2012. The sample consists of employed Americans 18years of age or older. The Emotional Health Index Scores are the sample space. We randomly sample one Emotional Health Index Score.

What occupation has the highest emotional index score?

The following table of data obtained from www.baseball-almanac.com shows hit information for four players. Suppose that one hit from the table is randomly selected.

Are "the hit being made by Hank Aaron" and "the hit being a double" independent events?

a. Yes, because P(hit by Hank Aaron | hit is a double) =P(hit by Hank Aaron)

b. No, because P(hit by Hank Aaron | hit is a double) P(hit is a double)

c. No, because P(hit is by Hank Aaron | hit is a double) P(hit by Hank Aaron)

d. Yes, because P(hit is by Hank Aaron | hit is a double) =P(hit is a double)

Write the symbols for the probability that a player is an outfielder and is a great hitter.

Use the following information to answer the next six exercises. There are 23countries in North America, 12countries in

South America, 47countries in Europe, 44countries in Asia, 54countries in Africa, and 14in Oceania (Pacific Ocean

region).

Let A = the event that a country is in Asia.

Let E = the event that a country is in Europe.

Let F = the event that a country is in Africa.

Let N = the event that a country is in North America.

Let O = the event that a country is in Oceania.

Let S = the event that a country is in South America.

Find P(A).

Forty-eight percent of all Californians registered voters prefer life in prison without parole over the death penalty for a person convicted of first degree murder. Among Latino California registered voters, 55%prefer life in prison without parole over the death penalty for a person convicted of first degree murder. 37.6%of all Californians are Latino. In this problem, let: • C = Californians (registered voters) preferring life in prison without parole over the death penalty for a person convicted of first degree murder. L = Latino Californians. Suppose that one Californian is randomly selected.

Find P(L AND C).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free