Seven hundred and seventy-one distance learning students at Long Beach City College responded to surveys in the $2010-11$academic year. Highlights of the summary report are listed in Table $1.39.$

a. What percent of the students surveyed do not have a computer at home?

b. About how many students in the survey live at least 16 miles from campus?

c. If the same survey were done at Great Basin College in Elko, Nevada, do you think the percentages would be the same? Why?

96% of the students have computer at home

$$\begin{gathered} \text{Percentwithoutcomputers}=100-\text{percentwithcomputers} \\ =100-96 \\ =4\% \end{gathered}$$

$771$students are there and $13\%$of them live at least $16$miles away from campus.

$$\begin{gathered} \text{Numberofstudents}=\text{Percentofstudents}\times \text{Totalnumberofstudents} \\ =\frac{13}{100}\times 771 \\ =100.23 \\ =101\text{students} \end{gathered}$$

Given the responses of seven hundred and seventy-one distance learning students at Long Beach City College responded to surveys in the $2010-11$academic year.

No, the percent would not be the same for the Great Basin College in Elko, because it would have a different total number of admissions. There would be different age groups, different distances, and the entire demographics and the attributes would vary as compared to the given scenario and hence we do not expect the percent to be the same.