What is the mean, standard deviation, and sample size?

Short Answer

Expert verified

The mean time for each review is4 hours and standard deviation is 1.2 hours and sample size is16.

Step by step solution

01

 Given information 

Given in the question that, Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2 hours. LetΧ be the random variable representing the time it takes her to complete one review. AssumeΧis normally distributed. Let x¯{"x":[[4,22,36],[6,35],[4.777605574440839,5.647456684472792,6.517307794504744,8.257010014568648,9.1268611246006,9.996712234632552,10.866563344664504,11.736414454696456,12.606265564728409,13.476116674760362,14.345967784792315,15.215818894824267,16.08567000485622,16.95552111488817,17.825372224920123,18.695223334952075,19.565074444984027,20.43492555501598,21.30477666504793,22.174627775079884,23.044478885111836,23.914329995143788,24.78418110517574,25.654032215207693,26.523883325239645,27.393734435271597,28.26358554530355,29.1334366553355,30.003287765367453,30.873138875399405,31.742989985431358,32.61284109546331]],"y":[[9,59,116],[115,9],[-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313]],"t":[[0,0,0],[0,0],[1648618415293,1648618415612,1648618415620,1648618415654,1648618415671,1648618415686,1648618415706,1648618415728,1648618415751,1648618415770,1648618415787,1648618415805,1648618415826,1648618415870,1648618415887,1648618415904,1648618415931,1648618415970,1648618415993,1648618416037,1648618416065,1648618416085,1648618416142,1648618416182,1648618416221,1648618416237,1648618416262,1648618416330,1648618416379,1648618416400,1648618416436,1648618416488]],"version":"2.0.0"}be the random variable representing the mean time to complete the 16 reviews. Assume that the 16 reviews represent a random set of reviews.

02

Explanation

According to the supplied facts, the manager reviews 16 employees each month. And reviews time is approximately 4 hours for each review with a population standard deviation of 1.2hours. Thus, the meantime for each review is 4hours and the standard deviation is1.2 hours, and sample size is16.

03

Final answer

The meantime for each review is 4hours and the standard deviation is 1.2 hours, and sample size is16.

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