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Chapter 7: Q.11 (page 428)

Find the probability that the sum of the 40 values is greater than7,500.

Short Answer

Expert verified

The probability that the sum of the 40 values is greater than 7500isP(X≥7500)=0.0089.

Step by step solution

01

Given Information

A mean (μx)is180and a standard deviation (σx) is 20and sample size (n)is40.

02

Explanation

To find the probability that the sum of the 40values is less than that 7500:

∑X~Nnμx,nσx

∑X~N((40)(180),(40)(20))

P(X≥7500)=PZ≥X-nμxnσx=PZ≥7500-7200126.4911=P(Z≥2.3717)

P(X≥7500)=0.0089

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