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Chapter 7: Q.16 (page 428)

Find the probability that the sum of the 100values is greater than 3,910.

Short Answer

Expert verified

The probability that the sum of the 100 values is greater than 3,910isP(X≥3910)=0.0359.

Step by step solution

01

Given Information

From the information given in the question, the mean is 39.01with a standard deviation of 0.5.

02

Explanation

To find the probability that the sum of the 100values is greater than3910:

∑X~Nnμx,nσx

∑X~N((100)(39.01),(100)(0.5))

P(X≥3910)=PZ≥X-nμxnσx=PZ≥3910-39015=P(Z≥1.8)

P(X≥3910)=0.0359

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