X~N(6,2)

Find the probability that xis between three and nine.

Short Answer

Expert verified

The probability that X is between 3 and 9is equal to0.87.

Step by step solution

01

Given Information

Let variable Xhas normal allocation with mean μand variance σ2.

Then probability density operation is determined by:

f(x)=12πσe-12(x-μ)2σ2,xR

02

Explanation

Let Xhas normal allocation with mean 6 and normal deviation 2,X~N6,22.

Now we require to find the probability that Xis between 3and 9.

We have the following:

P(3<X<9)=39f(x)dx

Substitute the given expression,

=3912π2e-12(x-6)222dx

=3612π2e-12x-622dx

u=x-62,du=12dx

03

Calculation

Substitute the given expression,

=-1.51.512πe-u22du

=NORMSDIST(1.5)-NORMSDIST(-1.5)

Substract the given expression,

=0.93-0.07

We get,

=0.87.

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IQ is normally distributed with a mean of 100and a standard deviation of 15. Suppose one individual is randomly chosen. Let X=IQof an individual.

a. X~_____(_____,_____)

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