Suppose \({\bf{x}}\) is an eigenvector of \(A\) corresponding to an eigenvalue \(\lambda \).

a. Show that \(x\) is an eigenvector of \(5I - A\). What is the corresponding eigenvalue?

b. Show that \(x\) is an eigenvector of \(5I - 3A + {A^2}\). What is the corresponding eigenvalue?

Short Answer

Expert verified

(a) It is proved that \(x\) is an eigenvector of \(5I - A\).Therefore,\(\;5 - \lambda \) is the eigenvalue.

(b) It is proved that \(x\) is an eigenvector of \(5I - 3A + {A^2}\). Therefore, \(5 - 3\lambda + {\lambda ^2}\) is the eigenvalue.

Step by step solution

01

Definition of matrix and eigenvalue

A matrix(plural matrices)is arectangular array or table ofnumbers,symbols, orexpressions, arranged in rows and columns, which is used to represent amathematical object or a property of such an object.

The eigenvalue \(\lambda \) is the real or complex number of a matrix \(A\) which is a square matrix that satisfies the following equation

\(\det \left( {A - \lambda I} \right) = 0\)

.

This equation is called the characteristic equation.

02

Find the eigenvector of matrix product

Let \(\lambda \) be an eigenvalue of the matrix \(A\). Then we have

\(Ax = \lambda x\)

(a)

Simplify \((5I - A)x\).

\(\begin{array}{r}(5I - A)x = 5x - Ax\\ = 5x - \lambda x\\ = (5 - \lambda I)x\\ = (5 - \lambda )x\end{array}\)

Therefore\(\;5 - \lambda \) is the eigenvalue.

b)

Consider,

\(\begin{array}{c}\left( {5I - 3A + {A^2}} \right)x = 5x - 3Ax + {A^2}x\\ = 5x - 3\lambda x + A\lambda x\\ = 5x - 3\lambda x + \lambda Ax\\ = 5x - 3\lambda x + {\lambda ^2}x\\ = \left( {5 - 3\lambda + {\lambda ^2}} \right)x\end{array}\)

Therefore \(5 - 3\lambda + {\lambda ^2}\) is the eigenvalue.

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Most popular questions from this chapter

Exercises 19–23 concern the polynomial \(p\left( t \right) = {a_{\bf{0}}} + {a_{\bf{1}}}t + ... + {a_{n - {\bf{1}}}}{t^{n - {\bf{1}}}} + {t^n}\) and \(n \times n\) matrix \({C_p}\) called the companion matrix of \(p\): \({C_p} = \left( {\begin{aligned}{*{20}{c}}{\bf{0}}&{\bf{1}}&{\bf{0}}&{...}&{\bf{0}}\\{\bf{0}}&{\bf{0}}&{\bf{1}}&{}&{\bf{0}}\\:&{}&{}&{}&:\\{\bf{0}}&{\bf{0}}&{\bf{0}}&{}&{\bf{1}}\\{ - {a_{\bf{0}}}}&{ - {a_{\bf{1}}}}&{ - {a_{\bf{2}}}}&{...}&{ - {a_{n - {\bf{1}}}}}\end{aligned}} \right)\).

20. Let \(p\left( t \right){\bf{ = }}\left( {t{\bf{ - 2}}} \right)\left( {t{\bf{ - 3}}} \right)\left( {t{\bf{ - 4}}} \right){\bf{ = - 24 + 26}}t{\bf{ - 9}}{t^{\bf{2}}}{\bf{ + }}{t^{\bf{3}}}\). Write the companion matrix for \(p\left( t \right)\), and use techniques from chapter \({\bf{3}}\) to find the characteristic polynomial.

Use mathematical induction to show that if \(\lambda \) is an eigenvalue of an \(n \times n\) matrix \(A\), with a corresponding eigenvector, then, for each positive integer \(m\), \({\lambda ^m}\)is an eigenvalue of \({A^m}\), with \({\rm{x}}\) a corresponding eigenvector.

Question: Is \(\left( {\begin{array}{*{20}{c}}1\\{ - 2}\\1\end{array}} \right)\) an eigenvector of\(\left){\begin{array}{*{20}{c}}3&6&7\\3&3&7\\5&6&5\end{array}} \right)\)? If so, find the eigenvalue.

Question: Find the characteristic polynomial and the eigenvalues of the matrices in Exercises 1-8.

  1. \(\left[ {\begin{array}{*{20}{c}}2&7\\7&2\end{array}} \right]\)

A particle moving in a planar force field has a position vector .\(x\). that satisfies \(x' = Ax\). The \(2 \times 2\) matrix \(A\) has eigenvalues 4 and 2, with corresponding eigenvectors \({v_1} = \left( {\begin{aligned}{{20}{c}}{ - 3}\\1\end{aligned}} \right)\) and \({v_2} = \left( {\begin{aligned}{{20}{c}}{ - 1}\\1\end{aligned}} \right)\). Find the position of the particle at a time \(t\), assuming that \(x\left( 0 \right) = \left( {\begin{aligned}{{20}{c}}{ - 6}\\1\end{aligned}} \right)\).

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