In Exercises 13-16, use a rectangular coordinator system to plot \(u = \left[ {\begin{array}{*{20}{c}}5\\2\end{array}} \right]\), \(v = \left[ {\begin{array}{*{20}{c}}{ - 2}\\4\end{array}} \right]\) and their images under the given transformation \(T\). (Make a separate and reasonably large sketch for each exercise.) Describe geometrically what \(T\) does to each vector \(x\) in \({\mathbb{R}^2}\).

\(T\left( x \right) = \left[ {\begin{array}{*{20}{c}}0&0\\0&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\end{array}} \right]\)

Short Answer

Expert verified

The transformation \(T\left( x \right)\) represents the projection on the \({x_2}\) axis.

Step by step solution

01

Finding the rectangular coordinate

For the rectangular coordinate\(u = \left[ {\begin{array}{*{20}{c}}5\\2\end{array}} \right]\), find the coordinate after thetransformation \(T\left( x \right) = \left[ {\begin{array}{*{20}{c}}0&0\\0&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\end{array}} \right]\).

\(\begin{aligned} T\left( x \right) &= \left[ {\begin{array}{*{20}{c}}0&0\\0&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}5\\2\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{0 \times 5 + 0 \times 2}\\{0 \times 5 + 1 \times 2}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}0\\2\end{array}} \right]\end{aligned}\)

02

Finding the rectangular coordinate

For therectangular coordinate \(v = \left[ {\begin{array}{*{20}{c}}{ - 2}\\4\end{array}} \right]\), find the coordinate after the transformation \(T\left( x \right) = \left[ {\begin{array}{*{20}{c}}0&0\\0&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\end{array}} \right]\).

\(\begin{aligned} T\left( x \right) &= \left[ {\begin{array}{*{20}{c}}0&0\\0&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}{ - 2}\\4\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{0 \times \left( { - 2} \right) + 0 \times 4}\\{0 \times \left( { - 2} \right) + 1 \times 4}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}0\\4\end{array}} \right]\end{aligned}\)

03

Finding the rectangular coordinate

The transformed coordinates \(\left[ {\begin{array}{*{20}{c}}0\\2\end{array}} \right]\) and \(\left[ {\begin{array}{*{20}{c}}0\\4\end{array}} \right]\) can be plotted as follows:

So, the transformation \(T\left( x \right)\) represents the projection on the \({x_2}\) axis.

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Most popular questions from this chapter

Find the general solutions of the systems whose augmented matrices are given in Exercises 10.

10. \(\left[ {\begin{array}{*{20}{c}}1&{ - 2}&{ - 1}&3\\3&{ - 6}&{ - 2}&2\end{array}} \right]\)

The solutions \(\left( {x,y,z} \right)\) of a single linear equation \(ax + by + cz = d\)

form a plane in \({\mathbb{R}^3}\) when a, b, and c are not all zero. Construct sets of three linear equations whose graphs (a) intersect in a single line, (b) intersect in a single point, and (c) have no points in common. Typical graphs are illustrated in the figure.

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Show that if ABis invertible, so is B.

Suppose an experiment leads to the following system of equations:

\(\begin{aligned}{c}{\bf{4}}.{\bf{5}}{x_{\bf{1}}} + {\bf{3}}.{\bf{1}}{x_{\bf{2}}} = {\bf{19}}.{\bf{249}}\\1.6{x_{\bf{1}}} + 1.1{x_{\bf{2}}} = 6.843\end{aligned}\) (3)

  1. Solve system (3), and then solve system (4), below, in which the data on the right have been rounded to two decimal places. In each case, find the exactsolution.

\(\begin{aligned}{c}{\bf{4}}.{\bf{5}}{x_{\bf{1}}} + {\bf{3}}.{\bf{1}}{x_{\bf{2}}} = {\bf{19}}.{\bf{25}}\\1.6{x_{\bf{1}}} + 1.1{x_{\bf{2}}} = 6.8{\bf{4}}\end{aligned}\) (4)

  1. The entries in (4) differ from those in (3) by less than .05%. Find the percentage error when using the solution of (4) as an approximation for the solution of (3).
  1. Use your matrix program to produce the condition number of the coefficient matrix in (3).

Suppose the coefficient matrix of a linear system of three equations in three variables has a pivot position in each column. Explain why the system has a unique solution.

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