Suppose\(A\) is the \(3 \times 3\) zero matrix (with all zero entries). Describe the solution set of the equation \(Ax = 0\).

Short Answer

Expert verified

The solution set of the equation \(Ax = 0\) consists of all vectors in \({\mathbb{R}^3}\).

Step by step solution

01

Write matrix \(A\) as an augmented matrix

Write matrix \(A\) as an augmented matrix \(\left[ {\begin{array}{*{20}{c}}A&0\end{array}} \right].\)

\(\left[ {\begin{array}{*{20}{c}}0&0&0&0\\0&0&0&0\\0&0&0&0\end{array}} \right]\)

02

Determine the basic variable and free variables

The variables corresponding to pivot columns in the matrix are called basic variables.The other variable is called a free variable.

Here, \({x_1},{x_2}\), and \({x_3}\) are free variables.

03

Determine the solution set of the equation \(Ax = 0\)

The general solution of the system is:

\(\begin{aligned}{c}x = \left[ {\begin{aligned}{*{20}{c}}{{x_1}}\\{{x_2}}\\{{x_3}}\end{aligned}} \right]\\ = {x_1}\left[ {\begin{aligned}{*{20}{c}}1\\0\\0\end{aligned}} \right] + {x_2}\left[ {\begin{aligned}{*{20}{c}}0\\1\\0\end{aligned}} \right] + {x_3}\left[ {\begin{aligned}{*{20}{c}}0\\0\\1\end{aligned}} \right]\end{aligned}\)

Each \(x\) in \({\mathbb{R}^3}\) satisfies \(Ax = 0\) if \(A\) is a \(3 \times 3\) zero matrix. Therefore, the solution set of the equation \(Ax = 0\) consists of all vectors in \({\mathbb{R}^3}\).

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Most popular questions from this chapter

Suppose a linear transformation \(T:{\mathbb{R}^n} \to {\mathbb{R}^n}\) has the property that \(T\left( {\mathop{\rm u}\nolimits} \right) = T\left( {\mathop{\rm v}\nolimits} \right)\) for some pair of distinct vectors u and v in \({\mathbb{R}^n}\). Can Tmap \({\mathbb{R}^n}\) onto \({\mathbb{R}^n}\)? Why or why not?

Suppose Ais an \(n \times n\) matrix with the property that the equation \(Ax = 0\)has only the trivial solution. Without using the Invertible Matrix Theorem, explain directly why the equation \(Ax = b\) must have a solution for each b in \({\mathbb{R}^n}\).

Let a and b represent real numbers. Describe the possible solution sets of the (linear) equation \(ax = b\). (Hint:The number of solutions depends upon a and b.)

In Exercises 11 and 12, determine if \({\rm{b}}\) is a linear combination of \({{\mathop{\rm a}\nolimits} _1},{a_2}\) and \({a_3}\).

11.\({a_1} = \left[ {\begin{array}{*{20}{c}}1\\{ - 2}\\0\end{array}} \right],{a_2} = \left[ {\begin{array}{*{20}{c}}0\\1\\2\end{array}} \right],{a_3} = \left[ {\begin{array}{*{20}{c}}5\\{ - 6}\\8\end{array}} \right],{\mathop{\rm b}\nolimits} = \left[ {\begin{array}{*{20}{c}}2\\{ - 1}\\6\end{array}} \right]\)

In Exercises 15 and 16, list five vectors in Span \(\left\{ {{v_1},{v_2}} \right\}\). For each vector, show the weights on \({{\mathop{\rm v}\nolimits} _1}\) and \({{\mathop{\rm v}\nolimits} _2}\) used to generate the vector and list the three entries of the vector. Do not make a sketch.

16. \({{\mathop{\rm v}\nolimits} _1} = \left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right],{v_2} = \left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\)

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