In Exercises 1-4, determine if the system has a nontrivial solution. Try to use a few row operations as possible.

2. \(\begin{aligned}{c}{x_1} - 3{x_2} + 7{x_3} = 0\\ - 2{x_1} + {x_2} - 4{x_3} = 0\\{x_1} + 2{x_2} + 9{x_3} = 0\end{aligned}\)

Short Answer

Expert verified

The system has only a trivial solution since it has no free variable.

Step by step solution

01

Convert the given system of equations into an augmented matrix

Anaugmented matrix for a system of equations is a matrix of numbers in which eachrowrepresents the constantsfrom one equation, and each column represents all thecoefficients for a single variable.

The augmented matrix \(\left( {\begin{array}{*{20}{c}}A&0\end{array}} \right)\) for the given system of equations \({x_1} - 3{x_2} + 7{x_3} = 0, - 2{x_1} + {x_2} - 4{x_3} = 0\),and \({x_1} + 2{x_2} + 9{x_3} = 0\) is represented as:

\(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&7&0\\{ - 2}&1&{ - 4}&0\\1&2&9&0\end{array}} \right]\)

02

Apply row operation

Perform an elementary row operation to produce the first augmented matrix.

Perform the sum of \(2\) times row 1 and row 2 at row 2.

\(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&7&0\\0&{ - 5}&{10}&0\\1&2&9&0\end{array}} \right]\)

03

Apply row operation

Perform an elementary row operation to produce the second augmented matrix.

Perform the sum of \( - 1\) times row 1 and row 3 at row 3.

\(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&7&0\\0&{ - 5}&{10}&0\\0&5&2&0\end{array}} \right]\)

04

Apply row operation

Perform an elementary row operation to produce the third augmented matrix.

Perform the sum of \(1\) times row 2 and row 3 at row 3.

\(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&7&0\\0&{ - 5}&{10}&0\\0&0&{12}&0\end{array}} \right]\)

05

Determine whether the given system has a nontrivial solution

It is known that the homogeneous equation \(Ax = 0\) has a nontrivial solutionif and only if the equation has at least one free variable.

The system has anontrivial solution if a column in the coefficient matrix does not construct a pivot column and the corresponding variable is free.

\(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&7&0\\0&{ - 5}&{10}&0\\0&0&{12}&0\end{array}} \right]\)

The system has only a trivial solution since it has no free variable.

Thus, the system of linear equations only has a trivial solution.

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Most popular questions from this chapter

Let \(T:{\mathbb{R}^n} \to {\mathbb{R}^n}\) be an invertible linear transformation. Explain why T is both one-to-one and onto \({\mathbb{R}^n}\). Use equations (1) and (2). Then give a second explanation using one or more theorems.

Use the accompanying figure to write each vector listed in Exercises 7 and 8 as a linear combination of u and v. Is every vector in \({\mathbb{R}^2}\) a linear combination of u and v?

8.Vectors w, x, y, and z

Let \(T:{\mathbb{R}^n} \to {\mathbb{R}^n}\) be an invertible linear transformation, and let Sand U be functions from \({\mathbb{R}^n}\) into \({\mathbb{R}^n}\) such that \(S\left( {T\left( {\mathop{\rm x}\nolimits} \right)} \right) = {\mathop{\rm x}\nolimits} \) and \(\)\(U\left( {T\left( {\mathop{\rm x}\nolimits} \right)} \right) = {\mathop{\rm x}\nolimits} \) for all x in \({\mathbb{R}^n}\). Show that \(U\left( v \right) = S\left( v \right)\) for all v in \({\mathbb{R}^n}\). This will show that Thas a unique inverse, as asserted in theorem 9. (Hint: Given any v in \({\mathbb{R}^n}\), we can write \({\mathop{\rm v}\nolimits} = T\left( {\mathop{\rm x}\nolimits} \right)\) for some x. Why? Compute \(S\left( {\mathop{\rm v}\nolimits} \right)\) and \(U\left( {\mathop{\rm v}\nolimits} \right)\)).

Suppose an experiment leads to the following system of equations:

\(\begin{aligned}{c}{\bf{4}}.{\bf{5}}{x_{\bf{1}}} + {\bf{3}}.{\bf{1}}{x_{\bf{2}}} = {\bf{19}}.{\bf{249}}\\1.6{x_{\bf{1}}} + 1.1{x_{\bf{2}}} = 6.843\end{aligned}\) (3)

  1. Solve system (3), and then solve system (4), below, in which the data on the right have been rounded to two decimal places. In each case, find the exactsolution.

\(\begin{aligned}{c}{\bf{4}}.{\bf{5}}{x_{\bf{1}}} + {\bf{3}}.{\bf{1}}{x_{\bf{2}}} = {\bf{19}}.{\bf{25}}\\1.6{x_{\bf{1}}} + 1.1{x_{\bf{2}}} = 6.8{\bf{4}}\end{aligned}\) (4)

  1. The entries in (4) differ from those in (3) by less than .05%. Find the percentage error when using the solution of (4) as an approximation for the solution of (3).
  1. Use your matrix program to produce the condition number of the coefficient matrix in (3).

Question: Determine whether the statements that follow are true or false, and justify your answer.

14: rank.|111123136|=3

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