Show that if ABis invertible, so is B.

Short Answer

Expert verified

Both AB and B are invertible.

Step by step solution

01

Write the algorithm for obtaining \({A^{ - 1}}\)

The inverse of an\(m \times m\)matrix A can be computed by using the augmented matrix\(\left[ {\begin{array}{*{20}{c}}A&I\end{array}} \right]\), where\(I\)is the identity matrix. Matrix Ahas an inverse only if \(\left[ {\begin{array}{*{20}{c}}A&I\end{array}} \right]\) is row equivalent to \(\left[ {\begin{array}{*{20}{c}}I&{{A^{ - 1}}}\end{array}} \right]\).

02

Show that A is invertible

Product AB is invertible, so there should be an inverse of matrix AB. Let D be the inverse matrix of AB.

Then, it can be represented as shown below:

\(\begin{array}{c}D\left( {AB} \right) = I\\\left( {DA} \right)B = I\end{array}\)

The equation\(\left( {DA} \right)B = I\) shows that matrix\(DA\)is the inverse of matrix B.

Therefore, B is invertible.

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Most popular questions from this chapter

Use matrix algebra to show that if A is invertible and D satisfies \(AD = I\) then \(D = {A^{ - {\bf{1}}}}\).

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