Chapter 2: Q2.9-20E (page 93)
In Exercises 19-24, justify each answer or construction.
What is the rank of a \({\bf{4}} \times {\bf{5}}\) matrix whose null space in three dimensional.
Short Answer
The dimension of the null space of A is 2.
Chapter 2: Q2.9-20E (page 93)
In Exercises 19-24, justify each answer or construction.
What is the rank of a \({\bf{4}} \times {\bf{5}}\) matrix whose null space in three dimensional.
The dimension of the null space of A is 2.
All the tools & learning materials you need for study success - in one app.
Get started for freeLet Abe an invertible \(n \times n\) matrix, and let \(B\) be an \(n \times p\) matrix. Explain why \({A^{ - 1}}B\) can be computed by row reduction: If\(\left( {\begin{aligned}{*{20}{c}}A&B\end{aligned}} \right) \sim ... \sim \left( {\begin{aligned}{*{20}{c}}I&X\end{aligned}} \right)\), then \(X = {A^{ - 1}}B\).
If Ais larger than \(2 \times 2\), then row reduction of \(\left( {\begin{aligned}{*{20}{c}}A&B\end{aligned}} \right)\) is much faster than computing both \({A^{ - 1}}\) and \({A^{ - 1}}B\).
Find the inverse of the matrix \(\left( {\begin{aligned}{*{20}{c}}{\bf{3}}&{ - {\bf{4}}}\\{\bf{7}}&{ - {\bf{8}}}\end{aligned}} \right)\).
Show that if the columns of Bare linearly dependent, then so are the columns of AB.
If Ais an \(n \times n\) matrix and the transformation \({\bf{x}}| \to A{\bf{x}}\) is one-to-one, what else can you say about this transformation? Justify your answer.
Let \(A = \left( {\begin{aligned}{*{20}{c}}3&{ - 6}\\{ - 1}&2\end{aligned}} \right)\). Construct a \({\bf{2}} \times {\bf{2}}\) matrix Bsuch that ABis the zero matrix. Use two different nonzero columns for B.
What do you think about this solution?
We value your feedback to improve our textbook solutions.