Use only the definition of affine dependence to show that anindexed set \(\left\{ {{v_1},{v_2}} \right\}\) in \({\mathbb{R}^{\bf{n}}}\) is affinely dependent if and only if \({v_1} = {v_2}\).

Short Answer

Expert verified

An indexed set \(\left\{ {{v_1},{v_2}} \right\}\) in \({\mathbb{R}^n}\) is affinely dependent if and only if \({{\bf{v}}_1} = {{\bf{v}}_2}\).

Step by step solution

01

State the condition for affinely dependence

The set is said to be affinely dependent if the set \(\left\{ {{{\bf{v}}_{\bf{1}}},{{\bf{v}}_{\bf{2}}},...,{{\bf{v}}_p}} \right\}\) in the dimension\({\mathbb{R}^n}\) exists such that for non-zero scalars\({c_1},{c_2},...,{c_p}\), the sum of scalars is zero i.e. \({c_1} + {c_2} + ... + {c_p} = 0\), and \({c_1}{{\bf{v}}_1} + {c_2}{{\bf{v}}_2} + ... + {c_p}{{\bf{v}}_p} = 0\).

02

Show affinely dependence

An indexed set \(\left\{ {{{\bf{v}}_{\bf{1}}},{{\bf{v}}_{\bf{2}}}} \right\}\)in\({\mathbb{R}^n}\)is affinely dependent if and only if\({{\bf{v}}_{\bf{1}}} = {{\bf{v}}_{\bf{2}}}\).

The set\(\left\{ {{{\bf{v}}_{\bf{1}}},{{\bf{v}}_{\bf{2}}}} \right\}\)in\({\mathbb{R}^n}\)exists if for non-zero scalars\({c_1}\)and\({c_2}\), the sum is zero i.e.\({c_1} + {c_2} = 0\)and\({c_1}{{\bf{v}}_1} + {c_2}{{\bf{v}}_2} = 0\).

Here,\({c_1} = - {c_2} \ne 0\). So,\({c_1}{{\bf{v}}_1} + {c_2}{{\bf{v}}_2} = 0\)can be written as shown below:

\(\begin{aligned}{}\left( { - {c_2}} \right){{\bf{v}}_1} + {c_2}{{\bf{v}}_2} = 0\\ - {c_2}{{\bf{v}}_1} + {c_2}{{\bf{v}}_2} = 0\\ - {c_2}\left( {{{\bf{v}}_1} - {{\bf{v}}_2}} \right) = 0\\{{\bf{v}}_1} - {{\bf{v}}_2} = 0\end{aligned}\)

So,\({{\bf{v}}_1} = {{\bf{v}}_2}\).

Thus, an indexed set \(\left\{ {{v_1},{v_2}} \right\}\) in \({\mathbb{R}^n}\) is affinely dependent if and only if \({{\bf{v}}_1} = {{\bf{v}}_2}\).

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Most popular questions from this chapter

Let \({\bf{x}}\left( t \right)\) be a cubic Bézier curve determined by points \({{\bf{p}}_o}\), \({{\bf{p}}_1}\), \({{\bf{p}}_2}\), and \({{\bf{p}}_3}\).

a. Compute the tangent vector \({\bf{x}}'\left( t \right)\). Determine how \({\bf{x}}'\left( 0 \right)\) and \({\bf{x}}'\left( 1 \right)\) are related to the control points, and give geometric descriptions of the directions of these tangent vectors. Is it possible to have \({\bf{x}}'\left( 1 \right) = 0\)?

b. Compute the second derivative and determine how and are related to the control points. Draw a figure based on Figure 10, and construct a line segment that points in the direction of . [Hint: Use \({{\bf{p}}_1}\) as the origin of the coordinate system.]

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12.a. The essential properties of Bezier curves are preserved under the action of linear transformations, but not translations.

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A quartic Bézier curve is determined by five control points,

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\({\bf{x}}\left( t \right) = {\left( {1 - t} \right)^4}{{\bf{p}}_0} + 4t{\left( {1 - t} \right)^3}{{\bf{p}}_1} + 6{t^2}{\left( {1 - t} \right)^2}{{\bf{p}}_2} + 4{t^3}\left( {1 - t} \right){{\bf{p}}_3} + {t^4}{{\bf{p}}_4}\)for \(0 \le t \le 1\)

Construct the quartic basis matrix \({M_B}\) for \({\bf{x}}\left( t \right)\).

Question: 1. Let Lbe the line in \({\mathbb{R}^{\bf{2}}}\) through the points \(\left( {\begin{array}{*{20}{c}}{ - {\bf{1}}}\\{\bf{4}}\end{array}} \right)\) and \(\left( {\begin{array}{*{20}{c}}{\bf{3}}\\{\bf{1}}\end{array}} \right)\). Find a linear functional f and a real number d such that \(L = \left( {f:d} \right)\).

Question 3: Repeat Exercise 1 where \(m\) is the minimum value of f on \(S\) instead of the maximum value.

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