Question: Let v be an element of the convex set S. prove that v is an extreme point of S if an only if the set \(\left\{ {{\bf{x}} \in S:{\bf{x}} \ne {\bf{v}}} \right\}\) is convex.

Short Answer

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The point v is an extreme point of S if and only if the set \(\left\{ {{\bf{x}} \in S:\,\,{\bf{x}} \ne {\bf{v}}} \right\}\) is convex.

Step by step solution

01

Check for T  (in S), which has elements y and z

Let y and z are in T, then \(\overline {yz} \subseteq S\), since S is convex.

If v is an extreme point of S, \(v \notin yz\), so \(\overline {yz} \subset T\).

So, T is convex.

02

Check whether the given set is convex or not

Let \({\bf{v}} \in S\), but not an extreme point of S. Then there are y and z in S such that \(v \in \overline {yz} \) with \(v \ne y\) and \(v \ne z\). It proves that T is not convex.

So, v is an extreme point of S if and only if the set \(\left\{ {{\bf{x}} \in S:\,\,{\bf{x}} \ne {\bf{v}}} \right\}\) is convex.

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Most popular questions from this chapter

In Exercises 21–24, a, b, and c are noncollinear points in\({\mathbb{R}^{\bf{2}}}\)and p is any other point in\({\mathbb{R}^{\bf{2}}}\). Let\(\Delta {\bf{abc}}\)denote the closed triangular region determined by a, b, and c, and let\(\Delta {\bf{pbc}}\)be the region determined by p, b, and c. For convenience, assume that a, b, and c are arranged so that\(\left[ {\begin{array}{*{20}{c}}{\overrightarrow {\bf{a}} }&{\overrightarrow {\bf{b}} }&{\overrightarrow {\bf{c}} }\end{array}} \right]\)is positive, where\(\overrightarrow {\bf{a}} \),\(\overrightarrow {\bf{b}} \) and\(\overrightarrow {\bf{c}} \)are the standard homogeneous forms for the points.

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[Hint:Consult Sections 3.2 and 3.3, including the Exercises.]

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