Question: In Exercise 5, determine whether or not each set is compact and whether or not it is convex.

5. Use the sets from Exercise 3.

Short Answer

Expert verified
  1. Not compact but convex
  2. Compact and convex
  3. Not compact but convex
  4. Not compact and not convex
  5. Not compact but convex

Step by step solution

01

Use Exercise 3(a)

(a)

Form Exercise 3(a), it is obtained that \(\left\{ {\left( {x,y} \right):y > 0} \right\}\) is open.

This set is convexas this is not closed and thus not bounded.

Hence, the set \(\left\{ {\left( {x,y} \right):y > 0} \right\}\) is not compactbut convex.

02

Use Exercise 3(b)

(b)

Form Exercise 3(b), it is obtained that the set \(\left\{ {\left( {x,y} \right):x = 2\,\,{\rm{and}}\,\,1 \le y \le 3} \right\}\) is closed.

This set is convex as it is closed and bounded.

Hence, the set \(\left\{ {\left( {x,y} \right):x = 2\,\,{\rm{and}}\,\,1 \le y \le 3} \right\}\) is compact and convex.

03

Use Exercise 3(c)

(c)

Form Exercise 3(c), it is observed that the set \(\left\{ {\left( {x,y} \right):x = 2\,\,{\rm{and}}\,\,1 < y < 3} \right\}\) is neither open nor closed.

This set is convex and bounded.

Hence, \(\left\{ {\left( {x,y} \right):x = 2\,\,{\rm{and}}\,\,1 < y < 3} \right\}\)not compact but convex.

04

Use Exercise 3(d)

(d)

Form Exercise 3(d), it is observed that the set \(\left\{ {\left( {x,y} \right):xy = 1\,\,{\rm{and}}\,\,x > 0} \right\}\) is closed.

This set is not convex and not bounded.

Hence, \(\left\{ {\left( {x,y} \right):y > 0} \right\}\) not compact and not convex.

05

Use Exercise 3(e)

(e)

Form Exercise 3(e), it is observed that the set \(\left\{ {\left( {x,y} \right):xy \ge 1\,\,{\rm{and}}\,\,x > 0} \right\}\) is closed.

This set is convex and not bounded.

Hence, \(\left\{ {\left( {x,y} \right):y > 0} \right\}\) is not compact but convex.

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Most popular questions from this chapter

Question: In Exercises 15-20, write a formula for a linear functional f and specify a number d, so that \(\left( {f:d} \right)\) the hyperplane H described in the exercise.

Let H be the column space of the matrix \(B = \left( {\begin{array}{*{20}{c}}{\bf{1}}&{\bf{0}}\\{ - {\bf{4}}}&{\bf{2}}\\{\bf{7}}&{ - {\bf{6}}}\end{array}} \right)\). That is, \(H = {\bf{Col}}\,B\).(Hint: How is \({\bf{Col}}\,B\) related to Nul \({B^T}\)? See section 6.1)

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