Question 9: Let \(S = \left\{ {\left( {x,y} \right):{x^{\bf{2}}} + {{\left( {y - {\bf{1}}} \right)}^2} \le {\bf{1}}} \right\} \cup \left\{ {\left( {{\bf{3}},{\bf{0}}} \right)} \right\}\). Is the origin an extreme point of \({\mathop{\rm conv}\nolimits} S\)? Is the origin a vertex of \({\mathop{\rm conv}\nolimits} S\)?

Short Answer

Expert verified

The origin is an extreme point, and it is not a vertex of the \({\mathop{\rm conv}\nolimits} S\).

Step by step solution

01

Extreme points of S

Theorem 15 states that consider \(S\) as a nonempty compact convex set.So, \(S\) is the convex hull of its profile (the set of extreme points of \(S\)).

02

Determine whether the origin an extreme point of \({\mathop{\rm conv}\nolimits} S\) and vertex of \({\mathop{\rm conv}\nolimits} S\)

Consider \(S\) as a convex set. A point pis referred to as extreme pointof \(S\) if pis not in the interior of any line segment that lies in \(S\).

More precisely, if \({\mathop{\rm x}\nolimits} ,y \in S\) and \({\bf{p}} \in \overline {{\mathop{\rm xy}\nolimits} } \), then \({\bf{p}} = {\mathop{\rm x}\nolimits} \) or \({\bf{p}} = {\mathop{\rm y}\nolimits} \). The set of all extreme points of \(S\)is called theprofileof \(S\).

The set \(S\) is convexif for each \({\bf{p}},{\bf{q}} \in S\), the line segment \(\overline {{\bf{pq}}} \) is contained in \(S\). The set of all convex combinations of points in a set \(S\) is called the convex hull of \(S\), represented by \({\mathop{\rm conv}\nolimits} S\).

Let \(S = \left\{ {\left( {x,y} \right):{x^2} + {{\left( {y - 1} \right)}^2} \le 1} \right\} \cup \left\{ {\left( {3,0} \right)} \right\}\).

The center of the equation \({{\mathop{\rm x}\nolimits} ^2} + {\left( {{\mathop{\rm y}\nolimits} - 1} \right)^2} = 1\) is \(\left( {0,1} \right)\) and radius is 1. Graph the set S as shown below:

The point \(\left( {0,0} \right)\) is an extreme point of the \({\mathop{\rm conv}\nolimits} S\). It is not the interior of any line segment that lies in \(S\).

A line segment through the circle contains zero as an endpoint but \(\left( {0,0} \right)\) is not a vertex of the \({\mathop{\rm conv}\nolimits} S\).

The line segment passes from origin to the point \(\left( {3,0} \right)\). Therefore, the origin is an extreme point and not a vertex of the \({\mathop{\rm conv}\nolimits} S\).

Thus, the origin is an extreme point and not a vertex of the \({\mathop{\rm conv}\nolimits} S\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free