Evaluate the expression $3-\left(-x\right)+8-10$ for the given value of x.

localid="1649147405006" $-3$

To add two numbers with similar signs, add their absolute values and keep the similar sign with the resulting number.

To add two numbers with opposite signs, subtract the absolute value of smaller number from absolute value of larger number and keep the sign of larger number with the resulting number.

The difference of the numbers $7-3=4$ is positive because the larger number is positive.

And the difference of the numbers $3-7=-4$ is negative because the larger number is negative.

To evaluate the expression $3-\left(-x\right)+8-10$, substitute – 3 for x in the given expression to get

$\begin{array}{c}3-\left(-x\right)+8-10=3-\left(-\left(-3\right)\right)+8-10\\ =3-\left(3\right)+8-10\\ =3-3+8-10\end{array}$

Now to simplify further, find the difference of first two numbers.

To subtract $3$, add its opposite $-3$ with first number and solve as follows

$\begin{array}{c}3-\left(-x\right)+8-10=3-3+8-10\\ =0+8-10\end{array}$

Now to simplify further, find the sum of first two numbers from left to right. Recall that 0 is the additive identity and when added or subtracted from any number, leaves the number unchanged. So, we have

$\begin{array}{c}3-\left(-x\right)+8-10=0+8-10\\ =8-10\end{array}$

Now, to subtract $10$, add its opposite $-10$and solve as follows

$\begin{array}{c}3-\left(-x\right)+8-10=8-10\\ =8+\left(-10\right)\\ =-2\end{array}$

Thus, the value of the expression is $-2$.