Chapter 4: Q2. (page 179)

Find two pairs of relatively prime numbers from $5, 10, 16 & 25$ .

Short Answer

Expert verified

The pairs of co prime are $5 - 16, 16 - 25$ .

Step by step solution

Step -1 - Apply the concept of Prime and co prime number

In this, simply use the concept of prime number and co prime number such that a number has two factors \[1\] and its number itself called prime number and Two integers are said to be co-prime (or relatively prime) if they do not share a common divisor different than $1$ .

Step -2 – Find the Factorization to find prime and co prime

Here, the numbers are $5, 10, 16 & 25$ .

Factorization of $5$ is $5 = 1 \times 5$ .

Factorization of $10$ is $10 = 1 \times 2 \times 5$ .

Factorization of $16$ is $16 = 1 \times 2 \times 2 \times 4$ .

Factorization of $25$ is $25 = 1 \times 5 \times 5$ .

Step -3 – Finding the common factor

Now, from the above factorization, it is seen that the two pair having common factor $1$ , which would become co – prime.

So, the pairs are $5 - 16, 16 - 25$ .

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Find two pairs of relatively prime numbers from $5, 10, 16 & 25$ .

Short Answer

Step by step solution

Step -1 - Apply the concept of Prime and co prime number

Step -2 – Find the Factorization to find prime and co prime

Step -3 – Finding the common factor

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Find two pairs of relatively prime numbers from 5,10,16&25.

Short Answer

Step by step solution

Step -1 - Apply the concept of Prime and co prime number

Step -2 – Find the Factorization to find prime and co prime

Step -3 – Finding the common factor

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Theoretical and Mathematical Physics

Applied Mathematics

Geometry

Logic and Functions

Decision Maths

Study anywhere. Anytime. Across all devices.

Find two pairs of relatively prime numbers from $5, 10, 16 & 25$ .