Which expression is the prime factorisation of 252?

F.$2^2\cdot 3^2\cdot 7^2$

G.$2^2\cdot 3^2\cdot 7$

H.$2\cdot 3^2\cdot 7$

I.$2\cdot 3^2\cdot 7^2$

In this, simply use the concept of prime factorization of the numbers by dividing the number by suitable digit of prime number to make the quotient small.

Here, the numbers is 252.

Simply divide the above number by suitable digit until to get the smallest quotient,

$\begin{array}{l}252÷2=126\\ 126÷2=63\\ 63÷3=21\\ 21÷3=7\\ 7÷7=1\end{array}$

Here is the list of all Positive Factors of 252 in numerical order: $2,2,3,3,7.$

So, on combining it becomes $2^2\cdot 3^2\cdot 7$.

F.$2^2\cdot 3^2\cdot 7^2$: It is the incorrect option because the correct factorisation is $2\times 2\times 3\times 3\times 7$.

G.$2^2\cdot 3^2\cdot 7$: It is the correct option because the correct factorisation is$2\times 2\times 3\times 3\times 7$.

H.$2\cdot 3^2\cdot 7$: It is the incorrect option because the correct factorisation is$2\times 2\times 3\times 3\times 7$.

I.$2\cdot 3^2\cdot 7^2$: It is the incorrect option because the correct factorisation is $2\times 2\times 3\times 3\times 7$.