Find the value of x. Then classify the triangle by its angle measures.

One angle of the triangle is$37°$.

Second angle is given as$x°$.

Third angle is given as$\left(3x+51\right)°$.

Sum of all angles of a triangle is$180°$.

The sum of all the angles of a triangle is$180°$.

This gives us,

$\begin{array}{l}{\left(3x+51\right)}^{°}+x^{°}+{37}^{°}={180}^{°}\\ 3x^{°}+{51}^{°}+x^{°}+{37}^{°}={180}^{°}\end{array}$

Add both numbers and both the x together will give us,

$4x{}^{\circ }+88{}^{\circ }=180°$

Subtract 88 from both the sides.

$4x{}^{\circ }+88{}^{\circ }-88{}^{\circ }=180{}^{\circ }-88°$

This gives us,

$4x{}^{\circ }=92°$

Now, divide both sides by 4.

$\frac{4x°}{4}=\frac{92°}{4}$

This will give us the value of x.

$x=23°$

Second angle of the triangle is given as $x°$ and the value of x is$23°$.

Since, the third angle of the triangle is given as$\left(3x+51\right)°$.

To find the value of the angle, multiply 3 with 23 and then add 51 to it.

$3\times 23{}^{\circ }+51{}^{\circ }=120°$

So, the third angle is$120°$.

The value of x is$x=23°$.

One angle is$37°$, second angle is localid="1649345362518" $23°$and the third angle is$120°$.

All the three angles of the triangle are different. Hence, it is a Scalene triangle.