Find the value of x. Then classify the triangle by its angle measures.

One angle of the triangle is$42°$.

Second angle is given as$2x°$.

Third angle is given as$x°$.

Sum of all angles of a triangle is$180°$.

The sum of all the angles of a triangle is$180°$.

This gives us,

$2x{}^{\circ }+x{}^{\circ }+42{}^{\circ }=180°$

Add both x together.

$3x+42{}^{\circ }=180°$

Subtract 42 from both the sides.

$3x+42{}^{\circ }-42{}^{\circ }=180{}^{\circ }-42°$

This gives us,

$3x=138°$

Now, divide both sides by 3.

$\frac{3x°}{3}=\frac{138°}{3}$

This will give us the value of x.

$x=46°$

Since, the other two angles of the triangle are 2x and x.

To find the value of the angle, multiply it with$46°$.

The angle of second side 2x.

Multiply 2 with 46.

$2x=2\times 46°$

Which gives us the value as$92°$.

The angle of the third side is x.

And the value of x is$x=46°$.

Which gives us the value as$46°$.

The value of x is$x=46°$.

One angle is$42°$, Second angle is $46°$and the third angle is$92°$.

All the three angles of the triangle are different. Hence, it is a scalene triangle.