Chapter 3: Q. 41 (page 122)

Algebra Basics Solve the equation. Check your solution. (Lesson 2.5)
$c + 12 = 23$

Short Answer

Expert verified

The solution for the equation $c + 12 = 23$ is $c = 11$ .

Step by step solution

. Separate the variable and constants

Write the original equation and separate the variables.

$\begin{array}{l} c + 12 = 23 [Writeoriginalequation.] \\ c + 12 - 12 = 23 - 12 [Subtract12fromeachside.] \end{array}$

. Simplify both sides

Simplify the equation on both sides to solve it.

$\begin{array}{l} c = 23 - 12 \\ c = 11 \end{array}$

Therefore, the solution of the equation is $c = 11$ .

. Check the solution

To check the solution, write the original equation and substitute the value of c.

$c + 12 = 23$

Now, substitute $c = 11$ and check the result.

$\begin{array}{l} c + 12 = 23 [Writeoriginalequation.] \\ 11 + 12 = 23 [Substitute 1 1forc.] \\ 23 = 23 \end{array}$

As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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Algebra Basics Solve the equation. Check your solution. (Lesson 2.5)
$c + 12 = 23$

Short Answer

Step by step solution

. Separate the variable and constants

. Simplify both sides

. Check the solution

One App. One Place for Learning.

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Algebra Basics Solve the equation. Check your solution. (Lesson 2.5)c+12=23

Short Answer

Step by step solution

. Separate the variable and constants

. Simplify both sides

. Check the solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Pure Maths

Applied Mathematics

Logic and Functions

Statistics

Calculus

Study anywhere. Anytime. Across all devices.

Algebra Basics Solve the equation. Check your solution. (Lesson 2.5)
$c + 12 = 23$