Chapter 14: Q. 25 (page 889)

In Problems 13–32, use the accompanying graph of y = f(x).
Does $\lim_{x \to 4} f (x)$ exist? If it does, what is it?

Short Answer

Expert verified

Yes limit exist and $\lim_{x \to 4} f (x) = 0 .$

Step by step solution

Step. 1 Given and limit

We are given with the graph of the function and to for the limit to exist LHL = RHL.

Step. 2 Calculating LHL and RHL

From the graph it is clear that,

$\lim_{x \to 4^{-}} f (x) = 0$ and $\lim_{x \to 4^{+}} f (x) = 0 .$

Since LHL = 0 and RHL = 0.

Therefore, the limit of the function exist at $x = 4$ and it is equal to 0.

$\lim_{x \to 4} f (x) = 0 .$

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In Problems 13–32, use the accompanying graph of y = f(x).
Does $\lim_{x \to 4} f (x)$ exist? If it does, what is it?

Short Answer

Step by step solution

Step. 1 Given and limit

Step. 2 Calculating LHL and RHL

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In Problems 13–32, use the accompanying graph of y = f(x).Does limx→4f(x)exist? If it does, what is it?

Short Answer

Step by step solution

Step. 1 Given and limit

Step. 2 Calculating LHL and RHL

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Logic and Functions

Statistics

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Geometry

Study anywhere. Anytime. Across all devices.

In Problems 13–32, use the accompanying graph of y = f(x).
Does $\lim_{x \to 4} f (x)$ exist? If it does, what is it?