The surface area S of a sphere of radius r feet isS=S(r)=4πr2. Find the instantaneous rate of change of the surface area with respect to the radius r atr=2.

Short Answer

Expert verified

If the Function for the surface area of a sphere is S=S(r)=4πr2then the instantaneous rate of change of the surface area with respect to the radius r at2will be16πft2ft

Step by step solution

01

Step 1. Given information 

Function for the surface area of a sphere is

S=S(r)=4πr2

Radiusr=2

02

Step 2. The surface area of a sphere

Substitute r=2in the function for the surface area of a sphere

S(r)=4πr2S(2)=4π(2)2 S(2)=16π

So surface area of the sphere at radiusr=2is16πft2

03

Step 3. Instantaneous rate of change of surface area

Use instantaneous rate of change formula with respect r at 2

localid="1647033413018" S'(c)=limrcS(r)-S(c)r-cS'(2)=limr2S(r)-S(2)r-2S'(2)=limr24πr2-16πr-2S'(2)=limr24π(r2-22)r-2S'(2)=limr24π(r+2)(r-2)r-2S'(2)=limr24π(r+2)S'(2)=4π(2+2)S'(2)=16π

So Instantaneous rate of change of surface area is16πft2ft

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