Chapter 14: Q. 44 (page 876)

Use a graphing utility to find the indicated limit rounded to two decimal places.
$\lim_{x \to - 1} \frac{x^{3} + x^{2} + 3 x + 3}{x^{4} + x^{3} + 2 x + 2}$

Short Answer

Expert verified

The limit rounded to two decimal places is $3.99$

Step by step solution

Step 1. Given information

The given limit is

$\lim_{x \to - 1} \frac{x^{3} + x^{2} + 3 x + 3}{x^{4} + x^{3} + 2 x + 2}$ .

Using a graphing utility we will find the table of values to find the value of the given limit.

Step 2. Table of values

The table of values for the given limit is:

Therefore $\lim_{x \to - 1} \frac{x^{3} + x^{2} + 3 x + 3}{x^{4} + x^{3} + 2 x + 2} = 3.99$

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Use a graphing utility to find the indicated limit rounded to two decimal places.
$\lim_{x \to - 1} \frac{x^{3} + x^{2} + 3 x + 3}{x^{4} + x^{3} + 2 x + 2}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Table of values

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Use a graphing utility to find the indicated limit rounded to two decimal places.limx→-1x3+x2+3x+3x4+x3+2x+2

Short Answer

Step by step solution

Step 1. Given information

Step 2. Table of values

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Calculus

Decision Maths

Geometry

Logic and Functions

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

Use a graphing utility to find the indicated limit rounded to two decimal places.
$\lim_{x \to - 1} \frac{x^{3} + x^{2} + 3 x + 3}{x^{4} + x^{3} + 2 x + 2}$