In Problems 53-56, use the properties of limits and the facts that

$$\begin{gathered} \underset{x\to 0}{\lim }\frac{\sin x}{x}=1 \\ \underset{x\to 0}{\lim }\frac{\cos x-1}{x}=1 \\ \underset{x\to 0}{\lim }\sin x=0 \\ \underset{x\to 0}{\lim }\cos x=1 \end{gathered}$$

$\underset{x\to 0}{\lim }\frac{3\sin x+\cos x-1}{4x}$

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