Chapter 10: Q 15. (page 643)

The graph of a parabola is given. Match graph to its equation.
and equations of the parabola are $A) y^{2} = 4 x C) y^{2} = - 4 x E) {(y - 1)}^{2} = 4 (x - 1) G) {(y - 1)}^{2} = - 4 (x - 1) B) x^{2} = 4 y D) x^{2} = - 4 y F) {(x + 1)}^{2} = 4 (y + 1) H) {(x + 1)}^{2} = 4 (y + 1)$

Short Answer

Expert verified

Given graph represent the graph of ${(x + 1)}^{2} = 4 (y + 1)$ .

Step by step solution

Step 1. Given information.

We have given graph is

and equations of the parabola are

Step 2. Concept used.

General equation of the parabola is, ${(x - h)}^{2} = 4 a (y - k) a n d {(y - k)}^{2} = 4 a (x - h)$

Step 3. Explanation.

We have graph of the parabola is,

This graph is opens down and vertex of the parabola is (-1, -1).

Graph is opens downward so a is negative (a < 0).

This graph represent the equation ${(x + 1)}^{2} = 4 (y + 1)$

Step 4. Conclusion.

Hence, equation of the graph

is ${(x + 1)}^{2} = 4 (y + 1)$ .

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The graph of a parabola is given. Match graph to its equation.
and equations of the parabola are $A) y^{2} = 4 x C) y^{2} = - 4 x E) {(y - 1)}^{2} = 4 (x - 1) G) {(y - 1)}^{2} = - 4 (x - 1) B) x^{2} = 4 y D) x^{2} = - 4 y F) {(x + 1)}^{2} = 4 (y + 1) H) {(x + 1)}^{2} = 4 (y + 1)$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Concept used.

Step 3. Explanation.

Step 4. Conclusion.

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The graph of a parabola is given. Match graph to its equation.and equations of the parabola areA)y2=4xC)y2=-4xE)(y-1)2=4(x-1)G)(y-1)2=-4(x-1)B)x2=4yD)x2=-4yF)(x+1)2=4(y+1)H)(x+1)2=4(y+1)

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Concept used.

Step 3. Explanation.

Step 4. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

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Study anywhere. Anytime. Across all devices.

The graph of a parabola is given. Match graph to its equation.
and equations of the parabola are $A) y^{2} = 4 x C) y^{2} = - 4 x E) {(y - 1)}^{2} = 4 (x - 1) G) {(y - 1)}^{2} = - 4 (x - 1) B) x^{2} = 4 y D) x^{2} = - 4 y F) {(x + 1)}^{2} = 4 (y + 1) H) {(x + 1)}^{2} = 4 (y + 1)$