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Chapter 10: Q. 18 (page 699)

In problems11-18, find an equation of the conic described. Graph the equation by hand.

Vertices at (0,1)and (6,1); asymptote the line3y+2x=9

Short Answer

Expert verified

The equation of the hyperbola is(x-3)29-(y-1)24=1

Step by step solution

01

Step 1. Given Information

Co-ordinate of vertices (0,1)&(6,1)

The given asymptote is3y+2x=9

02

Step 2. Calculation

Since (a+α,β)=(0,1)

and (a-α,β)=(6,1)

comparing the above two we get,

α=3,β=1,a=-3

03

Step 3. Calculation 

The asymptote is y=-23x+3

Then we get, a=-3,b=-2

then the equation is(x-3)29-(y-1)24=1

04

Step 4. Graph

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