Chapter 10: Q 38. (page 683)

$e = 1$ ; directrix is parallel to the polar axis $2$ units below the
pole.

Short Answer

Expert verified

The polar equation is

$r = \frac{2}{1 - \sin (θ)}$

Step by step solution

Step 1. Given information

$e = 1$ ; directrix is parallel to the polar axis $2$ units below the

pole.

Step 2. Identify e and p

It is given that

$e = 1$

And directrix is parallel to the polar axis $2$ units below the

pole

So, $p = 2$

Step 3. Set up the polar equation

It is given that

focus is at the pole.

The directrix is parallel to the polar axis $2$ units below the

pole.

So, we can apply standard polar equation formula

$r = \frac{e p}{1 - e \sin (θ)}$

Plug values $e = 1, p = 2$

$r = \frac{1 \times 2}{1 - 1 \sin (θ)} r = \frac{2}{1 - \sin (θ)}$

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$e = 1$ ; directrix is parallel to the polar axis $2$ units below the
pole.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Identify e and p

Step 3. Set up the polar equation

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e=1; directrix is parallel to the polar axis 2units below thepole.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Identify e and p

Step 3. Set up the polar equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Applied Mathematics

Mechanics Maths

Theoretical and Mathematical Physics

Decision Maths

Probability and Statistics

Study anywhere. Anytime. Across all devices.

$e = 1$ ; directrix is parallel to the polar axis $2$ units below the
pole.