Analyze each equation; that is, find the center, foci, and vertices of each ellipse. Graph each equation by hand. Verify your graph using a graphing utility.

2x2+3y2-8x+6y+5=0

Short Answer

Expert verified

The center of ellipse is at (2,-1), vertices are (2±3,-1)and the foci are (1,-1)and(3,-1)

The required graph is

Step by step solution

01

Step 1. Given Information 

The given equation is 2x2+3y2-8x+6y+5=0

02

Step 2. Calculation

Rewrite the given equation in the general form of equation of ellipse,

2x2-8x+3y2+6y=-52(x2-4x)+3(y2-2y)=-52(x2-4x+4)+3(y2+2y+1)=-5+8+32(x-2)2+3(y+1)2=62(x-2)26+3(y+1)26=66(x-2)23+(y-(-1))22=1

The major axis is parallel to x-axis.

Now, on comparing the obtained equation with the general form of equation, we get,

(h,k)=(2,-1)a=3,b=2c2=a2-b2c2=3-2c2=1c=1

The vertices of major axis are at(h±a,k)=(2-3,-1)and(2+3,-1)

And the foci are at point(h±c,k)=(1,-1)and(3,-1)

03

Step 3. Graph

On plotting all the points on the graph, we get the required graph as follows,

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