Iffx=2x2+3x+1and gx=x2+3x+2, solve:

Part (a): fx=0

Part (b):fx=gx

Part (c): fx>0

Part (d):fxgx

Short Answer

Expert verified

Part (a): When fx=0, then x=-12,-1.

Part (b): Whenfx=gx, then x=-1,1.

Part (c): When fx>0, then role="math" localid="1646574659662" x=,-1-12,.

Part (d): When fxgx, then x=(-,-1][1,).

Step by step solution

01

Part (a) Step 1. Solve the equation when fx=0.

Consider the given question,

fx=2x2+3x+1,gx=x2+3x+2

From the question,

fx=02x2+3x+1=02x2+2x+x+1=02xx+1+x+1=02x+1x+1=0x=-12,-1

02

Part (b) Step 1. Solve the equation when fx=gx.

Consider the given question,

fx=2x2+3x+1,gx=x2+3x+2

From the question,

fx=gx2x2+3x+1=x2+3x+2x2-1=0x+1x-1=0x=±1x=-1,1

03

Part (c) Step 1. Solve the equation when fx>0.

Consider the given question,

fx=2x2+3x+1,gx=x2+3x+2

From the question,

fx>02x2+3x+1>02x+1x+1>0x=,-1-12,

04

Part (d) Step 1. Solve the equation when fx≥gx.

Consider the given question,

fx=2x2+3x+1,gx=x2+3x+2

From the question,

fxgx2x2+3x+1x2+3x+22x2-x2+3x-3x+1-20x2-10x=(-,-1][1,)

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