Chapter 7: Q. 3 (page 485)

(a) $\sin \frac{π}{4} \cdot \cos \frac{π}{3} =$
(b) $\tan \frac{π}{4} - \sin \frac{π}{6} =__$

Short Answer

Expert verified

(a) $\sin \frac{π}{4} \cdot \cos \frac{π}{3} = \frac{1}{2 \sqrt{2}}$

(b)localid="1646824125334" $\tan \frac{π}{4} - \sin \frac{π}{6} = \frac{1}{2}$

Step by step solution

Part (a) Step 1. Find the value

We know,

$\sin \frac{π}{4} = \frac{1}{\sqrt{2}} \cos \frac{π}{3} = \frac{1}{2}$

Therefore,

$\sin \frac{π}{4} \cdot \cos \frac{π}{3} = \frac{1}{\sqrt{2}} \cdot \frac{1}{2} \sin \frac{π}{4} \cdot \cos \frac{π}{3} = \frac{1}{2 \sqrt{2}}$

Part (b) Step 1. Find the value

We know,

$\tan \frac{π}{4} = 1 \sin \frac{π}{6} = \frac{1}{2}$

Therefore,

localid="1646824093386" $\tan \frac{π}{4} - \sin \frac{π}{6} = 1 - \frac{1}{2} \tan \frac{π}{4} - \sin \frac{π}{6} = \frac{1}{2}$

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(a) $\sin \frac{π}{4} \cdot \cos \frac{π}{3} =$
(b) $\tan \frac{π}{4} - \sin \frac{π}{6} =__$

Short Answer

Step by step solution

Part (a) Step 1. Find the value

Part (b) Step 1. Find the value

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(a) sinπ4·cosπ3=______(b)tanπ4-sinπ6=________

Short Answer

Step by step solution

Part (a) Step 1. Find the value

Part (b) Step 1. Find the value

One App. One Place for Learning.

Most popular questions from this chapter

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(a) $\sin \frac{π}{4} \cdot \cos \frac{π}{3} =$
(b) $\tan \frac{π}{4} - \sin \frac{π}{6} =__$