Chapter 7: Q. 7 (page 464)

Two solutions of the equation $\sin θ = \frac{1}{2}$ are and .

Short Answer

Expert verified

Two solutions of the equation $\sin θ = \frac{1}{2}$ are $\frac{π}{6} and \frac{5 π}{6}$ .

Step by step solution

Step 1. Given Information

Two solutions of the equation $\sin θ = \frac{1}{2}$ are ____ and ____.

Step 2. The period of the sine function is 2π.

In the interval $[0, 2 π)$ , there are two angles $θ$ for which

$\sin θ = \frac{1}{2} : θ = \frac{π}{6}, θ = \frac{5 π}{6}$

Two solution of $\sin θ = \frac{1}{2}$ are $\frac{π}{6} and \frac{5 π}{6}$

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Two solutions of the equation $\sin θ = \frac{1}{2}$ are and .

Short Answer

Step by step solution

Step 1. Given Information

Step 2. The period of the sine function is 2π.

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Two solutions of the equation sinθ=12are ____ and ____.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. The period of the sine function is 2π.

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Two solutions of the equation $\sin θ = \frac{1}{2}$ are and .