Chapter 7: Q. 83 (page 504)

Use a graphing utility to solve the equation on the interval $0 \leq x \leq 2 π$ . Approximate any solutions rounded to two decimal places.
$\sin (x) = \ln (x)$

Short Answer

Expert verified

The solution set is $\{2.22\}$ .

Step by step solution

Step 1. Given information.

Consider the given question,

$\sin (x) = \ln (x), 0 \leq x \leq 2 π$

We can say,

$y_{1} = \sin (x) y_{2} = \ln (x)$

Plot the two equations,

Step 2. Plot the equations for the given interval.

Consider the given question,

The interval is $0 \leq x \leq 2 π$ .

On plotting the equations for the given interval,

From the graph, we can see the point of intersection is $(2.22, 0.8)$ .

Then the solution is $\{2.22\}$ .

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Use a graphing utility to solve the equation on the interval $0 \leq x \leq 2 π$ . Approximate any solutions rounded to two decimal places.
$\sin (x) = \ln (x)$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Plot the equations for the given interval.

One App. One Place for Learning.

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Use a graphing utility to solve the equation on the interval 0≤x≤2π. Approximate any solutions rounded to two decimal places.sinx=lnx

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Plot the equations for the given interval.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Decision Maths

Discrete Mathematics

Geometry

Pure Maths

Logic and Functions

Study anywhere. Anytime. Across all devices.

Use a graphing utility to solve the equation on the interval $0 \leq x \leq 2 π$ . Approximate any solutions rounded to two decimal places.
$\sin (x) = \ln (x)$