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Chapter 7: Q. 92 (page 496)

In Problems 79-90, find the exact value of each expression.

f(x)=cos(2x)+cosx

Short Answer

Expert verified

The real zeroes areπ,π3,5π3

Step by step solution

01

Given information

Given functionf(x)=cos(2x)+cosx

02

Rearranging and calculating the value

Rearranging, we get

f(x)=cos(2x)+cosxf(x)=2cos2x-1+cosx(cosx+1)(2cosx-1)=0cosx=-1cosx=12x=π,π3,5π3

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Most popular questions from this chapter

In Problems 9–36, find the exact value of each expression.

sincos-112

Multiply:sin(θ)1+cos(θ)1-cos(θ)1-cos(θ)

Find the value of the number C:

12cos2x+C=14cos2x

Show that the difference quotient for f(x)=cosxis given by


role="math" localid="1646431168099" f(x+h)-f(x)h=cos(x+h)-cos(x)h=-sinx·sinhh-cosx·1-coshh

Show that the difference quotient for

f(x)=sinx is given by

role="math" localid="1646430733990" f(x+h)-f(x)h=sin(x+h)-sin(x)h=cosx·sinhh-sinx·1-coshh
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