Chapter 7: Q. 92 (page 487)

solve each equation on the interval
$\sqrt{3} \sin θ + \cos θ = 1$

Short Answer

Expert verified

$θ = n π + {(- 1)}^{n} \frac{π}{6} - \frac{π}{6}$

Step by step solution

Step 1.Given information is

a trignometirc equation $\sqrt{3} \sin θ + \cos θ = 1$

Step 2. Multiplying both the side by 12

$\frac{\sqrt{3}}{2} \sin θ + \frac{1}{2} \cos θ = \frac{1}{2} \cos (\frac{π}{6}) \sin θ + \sin (\frac{π}{6}) \cos θ = \sin (\frac{π}{6}) \sin (θ + \frac{π}{6}) = \sin (\frac{π}{6})$

Step 3.The general solution we get is

$θ = n π + {(- 1)}^{n} \frac{π}{6} - \frac{π}{6}$

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solve each equation on the interval
$\sqrt{3} \sin θ + \cos θ = 1$

Short Answer

Step by step solution

Step 1.Given information is

Step 2. Multiplying both the side by 12

Step 3.The general solution we get is

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solve each equation on the interval 3sinθ+cosθ=1

Short Answer

Step by step solution

Step 1.Given information is

Step 2. Multiplying both the side by 12

Step 3.The general solution we get is

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

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Study anywhere. Anytime. Across all devices.

solve each equation on the interval
$\sqrt{3} \sin θ + \cos θ = 1$