Rewrite over a common denominator:

sin(θ)+cos(θ)cos(θ)+sin(θ)+cos(θ)sin(θ)

Short Answer

Expert verified

on simplifying over common denominator we get,

1+2sin(θ)cos(θ)sin(θ)cos(θ)

Step by step solution

01

Given information

We are given a equationsin(θ)+cos(θ)cos(θ)+sin(θ)+cos(θ)sin(θ)

02

On cross multiplying 

We get,

sin2(θ)+sin(θ)cos(θ)+sin(θ)cos(θ)+cos2(θ)sin(θ)cos(θ)=sin2(θ)+cos2(θ)+2sin(θ)cos(θ)sin(θ)cos(θ)=1+2sin(θ)cos(θ)sin(θ)cos(θ)

03

Conclusion

On simplifying we get1+2sin(θ)cos(θ)sin(θ)cos(θ)

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