Chapter 8: Q. 12 (page 516)

Find the exact value of the six trigonometric functions of the angle $θ$ in each figure.

Short Answer

Expert verified

The required trigonometric functions are:

$\sin θ = \frac{b}{c} = \frac{3}{3 \sqrt{2}} = \frac{1}{\sqrt{2}} c s c θ \frac{c}{b} = \frac{3 \sqrt{2}}{3} = \sqrt{2} \cos θ = \frac{a}{c} = \frac{3}{3 \sqrt{2}} = \frac{1}{\sqrt{2}} s e c θ = \frac{c}{a} = \frac{3 \sqrt{2}}{3} = \sqrt{2} \tan θ = \frac{b}{a} = \frac{3}{3} = 1 c o t θ = \frac{a}{b} = \frac{3}{3} = 1$

Step by step solution

Step 1. Given Information

We have, $a d j a c e n t, a = 3$ and $o p p o s i t e, b = 3$

Step 2. Formula Used

Pythagorean Theorem: $a^{2} + b^{2} = c^{2}$

where, $a, b a n d c$ are adjacent, opposite and hypotenuse respectively.

Trigonometric Functions:

$\sin θ = \frac{b}{c} c s c θ = \frac{c}{b} \cos θ = \frac{a}{c} s e c θ = \frac{c}{a} \tan θ = \frac{b}{a} c o t θ = \frac{a}{b}$

Step 3. Calculation

We need to find the hypotenuse, c first.

So using Pythagorean Theorem,

$a^{2} + b^{2} = c^{2}$

$3^{2} + 3^{2} = c^{2}$

$9 + 9 = c^{2}$

$c = \sqrt{18} c = 3 \sqrt{2}$

Now, the six trigonometric functions are:

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Find the exact value of the six trigonometric functions of the angle $θ$ in each figure.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Formula Used

Step 3. Calculation

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Find the exact value of the six trigonometric functions of the angle θin each figure.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Formula Used

Step 3. Calculation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

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Study anywhere. Anytime. Across all devices.

Find the exact value of the six trigonometric functions of the angle $θ$ in each figure.