Chapter 8: Q. 24 (page 516)

Find the exact value of the expression-
$1 + \tan^{2} 5 ° - c s c^{2} 85 °$

Short Answer

Expert verified

The required value is,

$1 + \tan^{2} 5 ° - c s c^{2} 85 ° = 0$

Step by step solution

Step 1. Given information

Given expression,

$1 + \tan^{2} 5 ° - c s c^{2} 85 °$

Step 2. Calculation

Solving the given expression,

$1 + \tan^{2} 5 ° - c s c^{2} 85 ° = s e c^{2} 5 ° - c s c^{2} 85 °$ ---------- $\{(1 + \tan^{2} θ = s e c^{2} θ)\}$

$= s e c^{2} (90 ° - 85 °) - c s c^{2} 85 ° = c s c^{2} 85 ° - c s c^{2} 85 ° = 0$ --------- $\{s e c (90 ° - A) = c s c A\}$

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Find the exact value of the expression-
$1 + \tan^{2} 5 ° - c s c^{2} 85 °$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Calculation

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