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Chapter 8: Q. 24 (page 527)

In the given problem solve the triangle using the law of sines : B=20°,C=70°,a=1

Short Answer

Expert verified

Required values of the triangle areA=90°,b=0.3,c=0.9

Step by step solution

01

Step 1. Given information

For a triangle with sides a, b, c and opposite angles A, B, C, respectively, Law of sines is given as:

sinAa=sinBb=sinCc

02

Step 2. Calculation

Given,B=20°,C=70°,a=1ForA,⇒A=180°-B-C=180°-20°-70°=90°Forc,⇒sinAa=sinCc⇒c=sinC×asinA=sin70°×1sin90°=0.9396×11=0.9396≈0.9Forb,⇒sinAa=sinBb⇒b=sinB×asinA=sin20°×1sin90°=0.342×11=0.342≈0.3

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