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Chapter 8: Q. 35 (page 541)

Cost of a Triangular Lot The dimensions of a triangular lot are 100 feet by 50 feet by 75 feet. If the price of such land is $3 per square foot, how much does the lot cost?

Short Answer

Expert verified

The cost of lot is $5446.38.

Step by step solution

01

Step 1. Given information.

Dimensions of a triangular lot are 100 feet by 50 feet by 75 feet.

Cost of land is $3 per square foot.

02

Step 2. Determine the semi perimeter of the triangular lot.

The semi perimeter of the triangular lot is:

s=a+b+c2=100+50+752=2252=112.5

03

Step 3. Determine the area of the triangle.

Area of the triangular lot is:

A=s(s-a)(s-b)(s-c)=112.5(112.5-100)(112.5-50)(112.5-75)=112.5(12.5)(62.5)(37.5)=3295898.4375≈1815.46

04

Step 4. Determine the cost of lot.

Cost of land is $3 per square foot. So, the total cost is:

Cost=$3×1815.46=$5446.38

The cost of lot is $5446.38.

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