Chapter 13: Q. 31 (page 865)

For Problems 31–34, the sample space is $S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}$ . Suppose that the outcomes are equally likely.
Compute the probability of the event $E = {1, 2, 3}$ .

Short Answer

Expert verified

The probability is $\frac{3}{10}$ .

Step by step solution

Step 1. Given information.

The sample space is $S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}$ . Suppose that the outcomes are equally likely.

Step 2. Find Probability.

Given that $S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and E = \{1, 2, 3\}$

So, $n (S) = 10 and n (E) = 3$

We need to find the probability of E. Thus we can use the formula

$P (E) = \frac{n (S)}{n (E)}$

Substitute the value of $n (S) a n d n (E)$ in the formula:

$P (E) = \frac{n (S)}{n (E)} = \frac{3}{10}$ .

Step 3. Conclusion.

The probability is $\frac{3}{10}$ .

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For Problems 31–34, the sample space is $S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}$ . Suppose that the outcomes are equally likely.
Compute the probability of the event $E = {1, 2, 3}$ .

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find Probability.

Step 3. Conclusion.

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For Problems 31–34, the sample space is S={1,2,3,4,5,6,7,8,9,10}. Suppose that the outcomes are equally likely.Compute the probability of the event E={1,2,3}.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find Probability.

Step 3. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Mechanics Maths

Geometry

Discrete Mathematics

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Statistics

Study anywhere. Anytime. Across all devices.

For Problems 31–34, the sample space is $S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}$ . Suppose that the outcomes are equally likely.
Compute the probability of the event $E = {1, 2, 3}$ .