Chapter 5: Q 57. (page 257)

In Problems 53–58, find functionsf and g so that $f \circ g = H$ .
$H (x) = |2 x + 1|$

Short Answer

Expert verified

The required functions are $f (x) = |x|; g (x) = 2 x + 1$ .

Step by step solution

Step 1. Given information.

The given function is:

$H (x) = |2 x + 1|$

In the given function H takes $2 x + 1$ and takes the absolute value of the function.

Now decompose H by taking the absolute value of the function.

Let's take $g (x) = 2 x + 1$ and $f (x) = |x|$ .

Step 2. Find f∘g.

$(f \circ g) (x) = f (g (x))$

Substitute $g (x) = 2 x + 1$ in the function $f (g (x))$ ,

Then the function will become $f (2 x + 1)$ .

Now replace x with $2 x + 1$ in $f (x) = |x|$ ,

$f (2 x + 1) = |2 x + 1| |2 x + 1| = H (x)$

As we can see that $f \circ g = H$ , therefore the values of the function that we assumed are correct.

$f (x) = |x|; g (x) = 2 x + 1$

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In Problems 53–58, find functionsf and g so that $f \circ g = H$ .
$H (x) = |2 x + 1|$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find f∘g.

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In Problems 53–58, find functionsf and g so that f∘g=H.H(x)=2x+1

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find f∘g.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Applied Mathematics

Mechanics Maths

Pure Maths

Decision Maths

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

In Problems 53–58, find functionsf and g so that $f \circ g = H$ .
$H (x) = |2 x + 1|$