Horizontal Stretches Open the horizontal stretch applet.

(a) Use your mouse to grab the slider and change the value of $a$. Note the role $a$plays in the graph of $g\left(x\right)=f\left(ax\right)=\sqrt{ax},$where $f\left(x\right)=\sqrt{x}$What happens to the points on the graph of $g$when $0<a<1$?

What happens to the points on the graph when $a>1$

(b) To further understand the concept of horizontal compressions, fill in the spreadsheet to the right of the graph as follows:

(i) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{2x}$, if the $y$-coordinate is to be $1$?

(ii) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{2x}$, if the $y$-coordinate is to be $2$?

(iii) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{2x}$, if the $y$-coordinate is to be $3$?

(iv) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{\frac{1}{2}x}$, if the $y$-coordinate is to be $1$?

(v) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{\frac{1}{2}}x$, if the $y$-coordinate is to be $2$?

(vi) What $x$-coordinate is required on the graph of $g\left(x\right)=\sqrt{\frac{1}{2}}x$, if the $y$-coordinate is to be $3$?

Step by step solution

01

Part (a) Step 1: Given information

Given the function$f\left(x\right)=\sqrt{x}$

02

Part (a) Step 2: Checking the value on various values

Here,

When $0<a<1$, stretch the graph $f$horizontally. When $a>1$, compress the graph $f$horizontally.

The graph is

03

Part (b) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{2x}$

04

Part (b) Step 2: Substitute g(x)=1 and calculate the value

Substituting, we get

$$\begin{gathered} \sqrt{2x}=1 \\ 2x=1 \\ x=\frac{1}{2} \end{gathered}$$

05

Part (b)(ii) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{2x}$

06

Part (b)(ii) Step 2: Substitute g(x)=2 and calculate the value

Substituting, we get

$$\begin{gathered} \sqrt{2x}=2 \\ 2x=4 \\ x=2 \end{gathered}$$

07

Part (b)(iii) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{2x}$

08

Part (b)(iii) Step 2: Substitute g(x)=3 and calculate the value

Substituting the value, we get

$$\begin{gathered} g\left(x\right)=\sqrt{2x} \\ 3=\sqrt{2x} \\ 2x=9 \\ x=\frac{9}{2} \\ x=4.5 \end{gathered}$$

09

Part (b) (iv) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{\frac{1}{2}}x$

10

Part (b)(iv) Step 2: Substitute g(x)=1 and calculate the value

Substituting, we get

$$\begin{gathered} g\left(x\right)=\sqrt{\frac{1}{2}}x \\ \sqrt{\frac{1}{2}x}=1 \\ \frac{1}{2}x=1 \\ x=2 \end{gathered}$$

11

Part (b)(v) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{\frac{1}{2}}x$

12

Part (b)(v) Step 2: Substitute g(x)=2 and calculate the value

Substituting, we get

$$\begin{gathered} g\left(x\right)=\sqrt{\frac{1}{2}}x \\ 2=\sqrt{\frac{1}{2}}x \\ \frac{1}{2}x=4 \\ x=8 \end{gathered}$$

13

Part (b)(vi) Step 1: Given information

Given the equation$g\left(x\right)=\sqrt{\frac{1}{2}}x$

14

Part (b)(vi) Step 2: Substituting g(x)=3 and calculating the value

Substituting, we get

$$\begin{gathered} g\left(x\right)=\sqrt{\frac{1}{2}}x \\ \sqrt{\frac{1}{2}x}=3 \\ \frac{1}{2}x=9 \\ x=18 \end{gathered}$$

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