Profit Function Suppose that the revenue R, in dollars, from selling x cell phones, in hundreds, is R(x)=-1.2x2+220x. The cost C, in dollars, of selling x cell phones is C(x)=0.05x3-2x2+65x+500.

(a) Find the profit function, role="math" localid="1646408711167" P(x)=R(x)-C(x).

(b) Find the profit if x=15hundred cell phones are sold.

(c) Interpret P(15).

Short Answer

Expert verified

(a) The profit function is P(x)=-0.05x3+0.8x2+155x-500

(b) The profit is $1836.25if x=15hundred cell phones are sold.

(c) When 15 hundred cellphones are sold, the profit is$1836.25.

Step by step solution

01

Step 1. Given Information

Profit Function Suppose that the revenue R, in dollars, from selling x cell phones, in hundreds, is role="math" localid="1646408800086" R(x)=-1.2x2+220x. The cost C, in dollars, of selling x cell phones is role="math" localid="1646408922328" C(x)=0.05x3-2x2+65x+500.

(a) Find the profit function, P(x)=R(x)-C(x).

(b) Find the profit if x=15hundred cell phones are sold.

(c) Interpret P(15).

02

Part (a) Step 1. We have to find the profit function P(x)=R(x)-C(x).

The value ofR(x)=-1.2x2+220xandC(x)=0.05x3-2x2+65x+500

03

Part (a) Step 2. Putting the value in the equation of profit.

P(x)=-1.2x2+220x-(0.05x3-2x2+65x+500)P(x)=-1.2x2+220x-0.05x3+2x2-65x-500

Simplify

role="math" localid="1646409621483" P(x)=-0.05x3+0.8x2+155x-500

04

Part (b) Step 1. We have to find the profit if x=15 hundred cell phones are sold.

Puttingx=15in the function of profit.

role="math" localid="1646409665519" P(15)=-0.05(15)3+0.8(15)2+155×15-500P(15)=-0.05×3375+0.8×225+155×15-500P(15)=-168.75+180+2325-500P(15)=1836.25
05

Part (c) Step 1. We have to interpret P(15).

When 15 hundred cellphones are sold, the profit is$1836.25.

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