Chapter 2: Q. 106 (page 71)

Are the functions $f (x) = x - 1$ and $g (x) = \frac{x^{2} - 1}{x + 1}$ the same? Explain.

Short Answer

Expert verified

The both functions are same.

Step by step solution

Step 1. Given Information

Are the functions $f (x) = x - 1$ and $g (x) = \frac{x^{2} - 1}{x + 1}$ the same? Explain.

Step 2. The given functions are f(x)=x-1 and g(x)=x2-1x+1.

Firstly solving the function $g (x)$ .

Using the formula $(a^{2} - b^{2}) = (a - b) (a + b)$

$g (x) = \frac{(x - 1) (x + 1)}{x + 1} g (x) = x - 1$

Step 3. The both functions are same.

Both functions are same because when we solve the function $g (x)$ , then $f (x) = g (x)$

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Are the functions $f (x) = x - 1$ and $g (x) = \frac{x^{2} - 1}{x + 1}$ the same? Explain.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. The given functions are f(x)=x-1 and g(x)=x2-1x+1.

Step 3. The both functions are same.

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Are the functions f(x)=x-1andg(x)=x2-1x+1 the same? Explain.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. The given functions are f(x)=x-1 and g(x)=x2-1x+1.

Step 3. The both functions are same.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Pure Maths

Statistics

Logic and Functions

Geometry

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Are the functions $f (x) = x - 1$ and $g (x) = \frac{x^{2} - 1}{x + 1}$ the same? Explain.