2. Let P=(x,y)be a point on the graph of y=x2-8.

(a) Express the distance dfrom Pto the point (0,-1)as a function of x.

(b) What is dif x=0?

(c) What is dif x=-1?

(d) Use a graphing utility to graph d=d(x).

(e) For what values of xis dsmallest?

Short Answer

Expert verified

The distance is d=x4-13x2+49and the values are7,6.08and the graph is

anddis least whenx=-2.55,x=2.55

Step by step solution

01

Part (a) Step 1: Given information

Given the pointP(x,y)and the curvey=x2-8

02

Part (a) Step 2: Calculate the distance using the distance formula

The distance of Pfrom (0,-1)is d=x2+(y-1)2. So the required distance is

d(x)=x2+x2-8+12d(x)=x2+x2-72d(x)=x2+x4-14x2+49d(x)=x4-13x2+49

03

Part (b) Step 1: Given information

Given the equationd(x)=x4-13x2+49

04

Part (b) Step 2: Substituting x=0 and calculating the value

Substituting, we get

d(x)=x4-13x2+49d(0)=04-13(0)2+49d(0)=49d(0)=7

05

Part (c) Step 1: Given information

Given the equationd(x)=x4-13x2+49

06

Part (c) Step 2: Substituting x=1 and calculating the value

Substituting, we get

d(x)=x4-13x2+49d(1)=14-13(1)2+49d(1)=37
07

Part (d) Step 1: Given information

Given the equationd(x)=x4-13x2+49

08

Part (d) Step 2: Sketching the graph

The graph is

09

Part (e) Step 1: Given information

Given the equationd(x)=x4-13x2+49

10

Part (e): Checking the graph

The value ofdis least whenx=-2.55,x=2.55

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