g(x)=x3-27x

(a) Determine whether the given function gis even, odd, or neither.

(b) There is a local minimum value of -54at 3. Determine the local maximum value.

Short Answer

Expert verified

Part (a). The given function g(x)is odd.

Part (b). The local maximum value is 54at x=-3.

Step by step solution

01

Part (a) Step 1. Given information

The given function is g(x)=x3-27xand the local miniumum is -54 at 3.

02

Part (a) Step 2. Find whether the given function g is even, odd, or neither.  

  • A function is even, ifg(-x)=g(x).
  • A function is odd, ifg(-x)=-g(x).

Replace xby -xin g(x).

g(-x)=(-x)3-27(-x)=-x3+27x=-(x3-27x)=-g(x)

Since g(-x)=-g(x), the given function is odd.

03

Part (b) Step 1. Determine the point of local maximum value.

Since is an odd function, conclude that the graph is symmetric with respect to the origin.

There is local minimum -54at x=3, so there is local maximum at x=-3.

04

Part (b) Step 2. Determine the local maximum value at the point x=-3. 

The function is odd, so g(-x)=-g(x).

This implies thatg(-3)=-g(3)(1).

Substitute the value of g(3)=-54into (1).

g(-3)=-g(3)=-(-54)=54

Hence, the local maximum value is 54at x=-3.

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