Effect of Gravity on Jupiter If a rock falls from a height of 20 meters on the planet Jupiter, its height H (in meters) after x seconds is approximately

H(x)=20-13x2

(a) What is the height of the rock when x=1second? x=1.1seconds?x=1.2 seconds?

(b) When is the height of the rock 15 meters? When is it 10 meters? When is it 5 meters?

(c) When does the rock strike the ground?

Short Answer

Expert verified

(a) The height of the rock when x=1is H(1)=7m, when x=1.1is H(1.1)=4.27m, when x=1.2is H(1.2)=1.28m.

(b) The height of the rock 15m in x0.62seconds, 10m in x0.88seconds, 5m in x1.08seconds.

(c) The rock strike the ground in x=1.24seconds.

Step by step solution

01

Step 1. Given Information

Effect of Gravity on Jupiter If a rock falls from a height of 20 meters on the planet Jupiter, its height H (in meters) after x seconds is approximately

H(x)=20-13x2

(a) What is the height of the rock when x=1second? x=1.1seconds? x=1.2seconds?

(b) When is the height of the rock 15 meters? When is it 10 meters? When is it 5 meters?

(c) When does the rock strike the ground?

02

Part (a) Step 1. The given function is H(x)=20-13x2We have to find the height of the rock when x=1 second.

Putting the value of xin the given function.

H(1)=20-13(1)2 H(1)=20-13×1H(1)=20-13H(1)=7

03

Part (a) Step 2. We have to find the height of the rock when   second.

Putting the value of xin the given function.

H(1.1)=20-13(1.1)2H(1.1)=20-13×1.21H(1.1)=20-15.73H(1.1)=4.27

04

Part (a) Step 3. We have to find the height of the rock when   second. 

Putting the value of xin the given function.

H(1.2)=20-13(1.2)2H(1.2)=20-13×1.44H(1.2)=20-18.72H(1.2)=1.28

05

Part (b) Step 1. We have to find the seconds x when the height of the rock 15 meters. 

Putting H(x)=15in given function

15=20-13x2

Subtract 20 on both side

15-20=20-13x2-20-5=-13x2

Divide by -13on both side

-5-13=-13-13x20.385x2x20.385

Taking square root on both side

x0.385x0.62

06

Part (b) Step 2. We have to find the seconds x when the height of the rock 10 meters. 

Putting H(x)=10in given function

localid="1646398133825" 10=20-13x2

Subtract 20 on both side

10-20=20-13x2-20-10=-13x2

Divide by -13on both side

localid="1646366229509" -10-13=-13-13x20.769x2x20.769

Taking square root on both side

localid="1646366265870" x0.769x0.88

07

Part (b) Step 3. We have to find the seconds x when the height of the rock 5 meters. 

Putting H(x)=5in given function

5=20-13x2

Subtract 20 on both side

5-20=20-13x2-20-15=-13x2

Divide by -13on both side

localid="1646366329071" -15-13=-13-13x21.154x2x21.154

Taking square root on both side

localid="1646366357100" x1.154x1.08

08

Part (c) Step 1. We have to find when does the rock strike the ground.When the rock strike the ground then H(x)=0

Putting H(x)=0in given function

0=20-13x2

Subtract 20 on both side

0-20=20-13x2-20-20=-13x2

Divide by -13on both side

-20-13=-13-13x21.538=x2x2=1.538

Taking square root on both side

x=1.538x=1.24

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