Chapter 2: Q. 98 (page 116)
Explain how the domain of compares to
Short Answer
The domain of $y=g(x)=\sqrt{x}$ ranges from 0 to $\infty$
where as the domain of $y=g(x-k) ; k \geq 0$ ranges from $k$ to $\infty$
Chapter 2: Q. 98 (page 116)
Explain how the domain of compares to
The domain of $y=g(x)=\sqrt{x}$ ranges from 0 to $\infty$
where as the domain of $y=g(x-k) ; k \geq 0$ ranges from $k$ to $\infty$
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Get started for freeIn Problems 7–18, match each graph to one of the following functions:
Find the following for each function:
Part (a):
Part (b):
Part (c):
Part (d):
Part (e):
Part (f):
In Problems write the function whose graph is the graph of but is:
Shifted to the right units
Consider the equation
Is this a function? What is its domain? What is its range? What is its y-intercept, if any? What are its x-intercepts, if any? Is it even, odd, or neither? How would you describe its graph?
Graph the function using the techniques of shifting, compressing, stretching, and/or reflecting. Start with the graph of the basic function and show all stages. Be sure to show at least three key points. Find the domain and the range of each function. Verify your results using a graphing utility.
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